Y=2x^2-2x^2-8x+8

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Solution for Y=2x^2-2x^2-8x+8 equation: 



=2Y^2-2Y^2-8Y+8

We move all terms to the left:

-(2Y^2-2Y^2-8Y+8)=0

We get rid of parentheses

-2Y^2+2Y^2+8Y-8=0

We add all the numbers together, and all the variables

8Y-8=0

We move all terms containing Y to the left, all other terms to the right

8Y=8

Y=8/8

Y=1

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